#SIN( Theta) .SIN (60-Theta).SIN(60+Theta)=1/4 sin 3theta

Prove that : `sin theta cos^3 theta - cos theta sin^3 theta = 1/4 sin4theta`.

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Prove: Cos^6 θ+ sin^6 θ= 1/4(1+3cos^2 2θ)

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proving SinA.Sin(60°-A).Sin(60°+A)=(1/4)Sin3A || Formula|| Trigonometry upto Transformations chapter

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If sin theta + sin^2 theta + sin^3 theta= 1, prove that cos^6 theta -4cos^4 theta + 8cos^2 theta=4.

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cos^2(θ)=1/4を解く

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sin 3x=3sinx -4sin^3 x と cos 3x = 4cos^3 x -3cos x の三角関数の恒等式を証明する方法