結果 : 1 upon 1 tan square theta is equal to
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Q48 | Prove that 1 - tan square theta by cot square theta - 1 = tan square theta | (1-tan^2⁡θ)/(cot^

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Q19 | Prove that 1 by 1 + tan square theta plus 1 by 1 + cot square theta = 1 | 1/(1+tan^2⁡θ)+1/(1 +

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Q3 | Prove that 1 + tan square theta into 1 - sin theta into 1 + sin theta = 1 | 1+tan^2⁡θ 1-sin⁡θ 1

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Q17 | Prove that sin square theta plus 1 by 1 + tan square theta = 1 | prove sin^2⁡θ+1/(1+tan^2⁡θ)=1

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Q30 | Prove that 1 + tan square theta by 1 + sec square theta = secθ | 1+tan^2⁡θ/(1+sec⁡θ)=sec⁡θ

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Q172 | Prove that 1 + tan square A by 1 + cot square A = 1 - tanA by 1 - cotA whole square = tan squ

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Q52 | Prove that (1-tan^2⁡θ)/(1+tan^2⁡θ)=cos^2⁡θ-sin^2⁡θ | 1 - tan square theta by 1 + tan square

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Q90 | Prove that (1+tan^2⁡θ)/(1+cot^2⁡θ)=((1-tan⁡θ)/(1-cot⁡θ))^2 | 1 + tan square theta by 1 + cot

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1+tan2A/1+cot2A=tan2A | 1+tan square A/1+cot square A | 1+tan2A/1+cot2A

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Q233 | Prove that: tan cube theta / 1 + tan square theta | tan ^3 theta / 1 + tan ^2 theta | Class X

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Q28 | Prove that 1 + tan square theta into cot theta by cosec square theta = tan theta

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Choose the correct option Justify your choice (iv) (1+Tan²A)/(1+Cot²A)

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Prove that tan cube theta divide by 1 + tan square theta plus cot | Trigonometry Important Questions

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Q27 | Prove that tan square theta - 1 upon cos square theta = -1 | Prove that tan^2⁡θ - 1/cos^2⁡θ=-1

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Prove (1+tan^2 A)/(1+cot^2 A)=((1-tanA)/(1-cotA))^2=tan^2 A| Ex 8.4 Q5 (x)

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10 cube theta upon 1 + 10 square theta + cot theta upon 1 + cot square theta equal to sec theta.....

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Basic Trigonometric Ratios:tan(theta), cot(theta), sin(theta), cos(theta), sec(theta), cosec(theta)

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(tan ∅)/(1-cot ∅)+(cot ∅)/(1-tan ∅)=1+Sec ∅ cosec ∅

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