find the value (125)2/3

Simplify:- (27/125)^(-2∕3) | 27 by 125 whole to the power -2 by 3

n^(3/2)=125を解く

125^(-2/3) を評価する

指数: 125^{-2/3} を簡略化します

Simplify 125^{2/3} | Simplifying surds

simplify (125)^-2/3 SEC 2 BSC #sec2 #bsc #SECBSC simplify(125) to the power -2 by 3

Q43 | Simplify (27/125)^(2/3)×(9/25)^(-3/2) | 27/125 to the power 2/3 x 9/25 to the power -3/2

Cognizant (CTS)/Cocubes Quantitative Aptitude Part 2

VIII Exponents and Powers Evaluate 64^2 3 + ∛ 125 + 3^0 + 1 2^ 5 + 27^ 2 3 x 25 9^ 1 2

Simplify ((25)^(5/2)×(729)^(1/3))/((125)^(2/3)×(27)^(2/3)×(8)^(4/3))

2 to the power of 3/2

Q101 | Simplify (64/125)^(-2/3)+(256/625)^(-1/4)+(3/7)^0 | 64/125 to the power -2/3 | 256/625 ^ -1/4

指数: 125^{1/3} を簡略化します

Simplify (64/125)^(-2/3)

分数の有理数乗、分数の分数乗の単純化

If (27)^999 is divided by 7, then the remainder is:

IF 125^x-1=25^2x-3 Then X=? | Time Saving Trick

ABACUS IN L.S.A.

Q36 | Evaluate (27/125)^(-2/3)÷(27/125)^(-4/3) | 27/125 to the power -2/3 | 27/125 power -4/3