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f(x) = 2x^2 - 3x + 5 の場合、f(x+1) を求めます。
関数を評価する方法を学ぶ
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両辺に変数があり、1 つの解がある方程式を解く
5x - (2x + 2) = x + (3x - 5) を x について解きます。
積と連鎖則を使用して 2 つの二項式の導関数を取得する
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Given f(x) = 2x - 3 and g(x) = x² - 5, find (f o g)(x)
𝗖𝗔𝗟𝗖𝗨𝗟𝗔𝗧𝗢𝗥 𝗧𝗘𝗖𝗛𝗡𝗜𝗤𝗨𝗘:𝗼𝗿𝗶𝗻𝗴 𝗤𝘂𝗮𝗱𝗿𝗮𝘁𝗶𝗰 𝗣𝗼𝗹𝘆𝗻𝗼𝗺𝗶𝗮𝗹𝘀
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