2x+4y=20 answer（関連順）

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Eq'n of d Circle which touch d Circle x²+y²–2x - 4y–20=0 externally at (5,5) with radius 5 @EAG

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30) Find the circle eqn which touchesthecircle x^2+y^2-2x-4y-20=0 externally at (5, 5) withradius 5

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「円は円 `x^2+y^2-2x+4y-20=0` と同心円である。半円の周囲が36であれば

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A ball moving around the circle `x^2+y^2 - 2x - 4y -20=0` in anticlockwise direction leaves it

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結果 : 2x+4y=20 answer