Integral of 3x sqrt(25 - x^2) dx , x = 0 to 4
25 の平方根を簡略化する方法: sqrt(25)
sqrt(75x^3)/sqrt(3x), square root of 75x^3 divided by square root of 3x
Trigonometric substitution: x over square root of {x^2-25}
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25の平方根
Solve by factorization: x^2+25x-10√5=0, √x2-2√2x-2√3=0, 4√x^2+5x-2√3=0, √2x^2+7x+5√2=0...
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なぜ sqrt(36) は正の 6 だけなのでしょうか
#5.平方根特性 (x + 4)^2 = -25 を使用して二次方程式を解く
Integral Practice #8: Indefinite Integral of (x^2(square root of (25 - x^2)))dx (trigo substitution)
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