If `5 cos 2theta + 2 cos^2 (theta/2) + 1 = 0`,`-pi lt theta lt pi` , then `theta` can be
sin square theta + cos square theta = 1 How to prove?
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If 2 sin^2 theta - cos^2 theta = 2, then find the value of theta
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The value of cos1° cos2° cos3° cos4°…………..…..cos90° is (a) 1 (b) 0 (c) – 1 (d) 2
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5 Given that sin θ + 2 cos θ = 1, then prove that 2 sin θ – cos θ = 2
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