[IIT 1994] Find the value of tan [ arccos { 1/[5*sqrt(2)] } - arcsin { 4/sqrt(17) } ].

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Show that:tan(1/2 sin^(-1) 3/4)= (4-sqrt 7)3, #themathsgurudev, CLASS 12 MATHEMATICS, INVERSE TRIGO

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If `sin^-1(1/3)+sin^-1 (2/3)= sin^-1 x` then x is equal to (A) `(4+sqrt(5)/9` (B) `(4sqrt(2)

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タン(sin^-1(1/3))

Show that: `tan(1/2sin^(-1)3/4)=(4\ sqrt(-7))/3`

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sin(cos^-1(1/2) + sin^-1(3/5)) の正確な値 三角関数逆複角

` 9pi/8 - 9/4 sin ^(-1) (1/3) = 9/4 sin ^(-1) (2 sqrt(2)/3)`

∫x/(1 - x⁴) dx. MIT Integration Bee 2013, Question 21, Qualifying Exam (Inverse Hyperbolic Tangent)

If the sum of two unit vectors is a unit vector, then magnitude of difference is

Question#4 - Laplace Transform - Application to Ordinary Differential Equation.

Last Day of Exams at IIT Delhi 😫🔥🥳 #minivlog #short #iit #collegelife

If g(x) = x sin^(x/4) + sqrt(16-x^2) find g’(2). Inverse Trig Functions. Find derivative, evaluate 2