cot(sin^-1(-1/2)) 正確な値を求める

The value of `cot[1/2 (sin^-1) sqrt3/2]` is

三角法: Cot 7 1/2 度の値。

If \( \cot A+\frac{1}{\cot A}=2 \), find the value of \( \cot ^{2} A+\frac{1}{\cot ^{2} A} \)

If sin θ= 1/3, then find the value of 2 cot^2 θ+2.

Evaluate the following : `sin { 1/2 cot^(-1) . ((-3)/4)}`

find the value of cot 7(1/2) degree class 11th | value of cot 7½°/ tan 7½°

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12th Std Maths Ex.4.4(2)(iii) Find the value of cot^-1(1)+ sin^-1(√3/2)-sec^-1(-√2)

cot(tan^(-1)a+cot^(-1)a) | the value of cot(tan inverse a + cot inverse a) |

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If cot^4A + cot^2 = 1, then find the value of cos^4A – 3 cos^2A.

The value of `sin(cot^-1x)=` (A) `sqrt(1+x^2)` (B) x (C) `(1+x^2)^(-3/2)` (D) `(1+x^2)^(-1/2)`

If sin A = 1/2 , then the value of cot A is (A) √3 (B)1/√3 (C)√3/2 (D) 1

If sin A = 1/2 , then the value of cot A is(A) ✓3 (B) 1/✓3 (C) ✓3/2 (D) 1

Value of sin(cot^-1 (cos ( tan^-1 1))) - Inverse Trigonometry - Class 12 Mathematics

2 If sin A = 1/2, the the value of cot A is

Find the principal values of cot-1(-1/√3) | Find the principal value of cot-1(-1/sqrt3)

If cotA + 1/CotA=2, Find the value of (cot^2A+1/cot^2A) CBSE, 2019,|Important question Class 10|