cot(3π/2-x)=?,Trigonometry,m aths,class-11,General aptitude,cot(2π-x),cot(π/2+x)

'cos(3pi2 + x) cos(2pi + x )[ cot(3pi2- x) + cot(2pi + x)] = 1'||

Cofunction Trigonometric Identity Explanation sin(3pi/2 - x)

cot(270 + x) | cot(3pi/2 + x) | cot(270 + A) | cot(3pi/2 + A) | cot(270 + theta)

9. Prove that cos (3pi/2 + x) cos (2pi + x) { cot (3pi/2 - x) + cot (2 pi +x)} =1

Prove that : sec (3π/2 - x) sec(x - 5π/2) + tan(5π/2 + x) tan((x - 3π/2) = -1

`cos((3pi)/(2) +x) cos(2pi+x)[cot(3pi)/(2)-x+cot(2pi+x)]=1`

Prove that: `cos((3pi)/2+x)cos(2x+x)[cot((3pi)/2-x)+cot(2pi+x)]=1`...

9. cos(3π/2+x) cos⁡(2π+x) [cot⁡(3π/2-x)+cot⁡(2π+x) ]=1

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prove cos(x - 3pi/2) = -sinx

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次を証明してください: `cos((3pi)/2+x)cos(2x+x)[cot((3pi)/2-x)+cot(2pi+x)]=1`...

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cos(3pi/2 - x) | cos(3pi/2 - theta)

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cot(270 – x) | cot(3pi/2 – x) | cot(270 – A) | cot(3pi/2 – A) | cot(270 – theta)

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