If `y=cos(sinx^2)`,then at `x=sqrt((pi)/(2))`,`(dy)/(dx)=`

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If `y=cos(sinx^2)` then at `x=sqrt(pi/2), (dy)/(dx)=`

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If ` y = log (sin (x^(2))), 0 lt x lt (pi)/(2), "then " (dy)/(dx) "at x " = (sqrt(pi))/(2) ` is

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If `f(x)=9-sinx+x^2` then at `x=pi`