y=x e^x sinx の場合、dy/dx を見つけます||Engg Maths-1||微分||タミル語
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d^2y/dx^2+3dy/dx+2y=xe^xSinx, (D^2+3D+2)y=xe^xSinx #HigherOrderLinearDifferentialEquation L881
y の導関数 = e^x*sinx
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IIT Bombay CSE 😍 #shorts #iit #iitbombay
Derivative of e^sinx with Chain Rule | Calculus 1 Exercises