log√1+sinx/1-sinx then diff. with respect to x/if log root 1+sinx devided by 1- sinx the find dy/dx

Find `(dy)/(dx)`,when `y = sqrt((1-sinx)/(1+sinx))`

Differentiation of root under 1+sinx/1-sinx

1/(1-sinx) を積分する方法

Prove that Cot inverse (√1+Sinx + √1-Sinx)/(√1+Sinx - √1-Sinx) = x/2

100 の微積分の導関数 (究極の導関数チュートリアル)

Find `(dy)/(dx)` when : `y=log sqrt((1+sinx)/(1-sinx))`

How to Integrate cosx/(1-sinx )(2-sinx)

Find the derivative cosx/1+sinx

(1+sinx)^1/2 の展開 (マクローリン級数)-[ ヒンディー語 ]

If y = tan⁻¹[ cosx/(1 + sinx)] , Find dy/dx

sec x + Tan x = cos x / (1 - sin x) を証明します。

Differentiate tan ^(-1)⁡ ((1+cos⁡x)/sin⁡x ) with respect to x | tan inverse 1 + cos x by sin x

Differentiation and integration important formulas||integration formula

That's Why Mohit Sir Called "God Of Mathematics"| Puzzle Brain teaser | #competishun #shorts #tricks

sin(x) の導関数の証明 |デリバティブのご紹介 | AP微積分AB |カーンアカデミー

"Find `(dy)/(dx)`of `y=(log)_e(sqrt((1+sinx)/(1-sinx)))`"

when calculus students use trig identities too early

` y=log ((1-sin x )/(1+sin x )),then (dy)/(dx) =`

यदि (If) `y=tan^(-1)sqrt((1+sinx)/(1-sinx)),` (find) `(dy)/(dx)` ज्ञात करें।