The differential equation find a particular solution satisfying the given condition: dy/dx-3y cot x

15. dy/dx- 3y cot⁡〖x=sin⁡〖2x;y=2 when x= π/2〗 〗

'dy/dx-3ycotx=sin2x' y=2 when x=pi/2 || '(dy/dx)-3ycotx=sin2x' ||'dy/dx-3ycotx=sin2x' ||

हल करें: `(dy)/(dx) -3y cot x = sin 2x` यदि यह दिया है की `y=2` जब `x=pi/2`:

If y (x) satisfies the differential equation `(dy)/(dx) =sin 2x + 3y cot x and

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Ex9.6/Q15/dy/dx -3ycotx=sin2x

` (dy)/(dx) + y cot x = sin 2x `

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Solve the following differential equation `(dy)/(dx)+ycotx=sin2x`