Integrate the functions ∫ 1/root over 9+8x-x^2 dx
#integrate 1/ square root 8-4x-2x² dx #shorts_question #Indefinite Integral
評価: `intdx/sqrt (10-8x-2x^2)`
int1/(sqrt(9+8x-4x^2))dx を評価する | クラス 12 | 積分法 | 数学 | Doubtnut
Trig Substitution | y=(x^2)/[sqrt(9-x^2)]
Integral of 1 / sqrt( x^8 - x^2 )
Integral by substitution - Integral( dx/sqrt (8-x^2)
出生の積分(9-8倍)
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検索: int sqrt(x^(2) - 8x - 9) dx | 12 | 積分 | 数学 | MITTAL 出版 | 疑問...
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