Evaluate : `intsqrt(1-sin2x)dx`.

Q58 | ∫√(1+sin⁡2x) dx | Integration of under root 1+ sin⁡ 2x | Integral of under root 1 + sin 2x

Q59 | ∫√(1-sin⁡2x) dx | Integration of under root 1 - sin⁡ 2x | Integral of under root 1 - sin 2x

Evaluate : integrate sqrt(1 - sin 2x) dx

Integral of sqrt(1-sin2x)dx

Integral of sqrt(1 - sin 2x)

`int sqrt(1 + sin 2x) dx` =

Integral root of 1-sin2x dx | 2 marks problem @EAG

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Evaluate ` int sqrt(1+sin. x/2 ) dx `

Integrate 0 to pi/2 sqrt(1-sin 2x) dx

` int sqrt (1 -sin 2x) dx` का समाकलन कीजिए ।

JEE MAINS 2018 Evaluate: `int_0^(pi//4)sqrt(1+sin2x)dx` (ii) `int_0^(pi//4)sqrt(1-sin2x)dx`

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Prove that : int_0^(pi/2)sqrt(1-sin2x)dx=2(sqrt(2)-1) | CLASS 12 | INTEGRALS | MATHS | Doubtnut

Integral of sqrt(1 - sin 2x)

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Q11 | Evaluate the definite Integral from 0 to π/4 √(1-sin2x) | limit 0 to π/4 int of (1-sin2x)^1/2