Differentiate w.r.t. x sqrt(x^2+4x-7)

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37. If 4x-9≤f(x)≤x^2-4x+7 for x≥0, find lim(x→4)⁡f(x).

平方完成法で方程式 x^2 + 4x - 7 = 0 を解く

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If `f` is defined by `f(x)=x^2-4x+7,` show that `f^(prime)(5)=2f^(prime)(7/2)`

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y=`sqrt[4x^2-7]`

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Find the derivative dy/dx using chain rule for y = x^3 (2x -5)^4