結果 : find the sum of n terms of the series 1 * 2 2 * 3 3 * 4
4:26

Find the sum to n terms | 1.2 + 2.3 + 3.4 + 4.5 + ….. | Sequence and Series | NCERT | Std 11 | Maths

Hi-Q Learning
4,623 回視聴 - 2 年前
10:03

find the sum of the series | 1.2.3 + 2.3.4 +to 3.4.5 + ..... to n terms | Sequence |Series

Hi-Q Learning
2,578 回視聴 - 2 年前
3:27

find the sum of the series upto n terms `1+(1+2)/2+(1+2+3)/3+(1+2+3+4)/4+......`

Doubtnut
4,075 回視聴 - 6 年前

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2:15

n 項の合計を求めます: (1^2).2 + (2^2).3 + (3^2).4 + ...

mathmuni
1,790 回視聴 - 12 年前
2:35

Find the sum to n terms 1 + 2x + 3*square(x) + 4*cube(x) + ...

mathmuni
342 回視聴 - 12 年前
5:28

4.c) 1².2 + 2².3 + 3².4 + .... Sum to n terms of following series 1^2.2 + 2^2.3 + 3^2.4 +....Find Sn

Simply Australia Things
8,260 回視聴 - 3 年前

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2:12

「級数 `1/2+3/4+7/8+(15)/(16)+` の最初の `n` 項の合計は (1988, 2M) `2^n-n-1

Doubtnut
391 回視聴 - 5 年前
8:22

find the sum of the series | 1^2 + (1^2 + 2^2 ) + (1^2 + 2^2 + 3^2) +… to n terms | Sequence |Series

Hi-Q Learning
623 回視聴 - 2 年前
4:04

Find the sum to n terms of the series : `1+2x+3x^2+4x^3+......`

Doubtnut
9,857 回視聴 - 6 年前
6:19

Q1. Find the sum to n terms of the series 1 x 2 + 2 x 3 + 3 x 4 + 4 x 5 + |Ex 9.4 Class 11 | Ncert

MATHEMATICAL AREA
5,224 回視聴 - 3 年前
4:08

The sum to n terms of the series` 1/2+3/4+7/8+15/16+..... is given by`

Doubtnut
5,617 回視聴 - 6 年前
5:05

Sum of the following series `1+2/2+3/(2^2)+4/(2^3)+...` to n terms

Doubtnut
4,186 回視聴 - 6 年前
2:14

The sum of the first n terms of the series 1/2+3/4+7/8+15/16+……… is (1) 2^n-n-1 (2) 1-2^-n (3) n+...

PW Solutions
5,130 回視聴 - 2 年前
2:33

n 項の合計を求めます 1/2 + 3/4 + 7/8 + 15/16 + ...

mathmuni
68,372 回視聴 - 13 年前
1:45

Find the sum of first n terms and the sum of first 5 terms of the geometric series 1 + `2/3` +`4...

Doubtnut
4,364 回視聴 - 7 年前
6:49

2.g) 2 + (2+3) + (2+3+4) + .... find the nth term and then sum of first n terms of each of series.

Simply Australia Things
17,420 回視聴 - 3 年前
7:54

Find sum to n terms of the series `3+5xx1/4+7xx1/(4^2)+........`

Doubtnut
214 回視聴 - 6 年前
4:57

The sum of the first n terms of the series 1^2+ 2.2^2+3^2 +2.4^2+.... is (n(n+1)^2)/2when n is ...

Doubtnut
3,264 回視聴 - 2 年前
10:12

Sum to n terms of the series- 1^2-2^2+3^2-4^2+5^2-6^2.....

Mathematics & Candy Crush
5,295 回視聴 - 6 年前
2:23

The sum to infinite term of the series 1+ 2/3+6/3²+10/3³+14/3^4 +⋯ is ?

Math Master - Impetus Gurukul
29,983 回視聴 - 4 年前