`cos^2(pi/6+theta)-sin^2\ (pi/6-theta)` の値は `adot1/2cos\ 2theta` b. `0` c. `-1/2c` です

The value of `cos^2(pi/6+theta)-sin^2(pi/6-theta)` is

'sin^2(pi/6)+cos^2(pi/3)- tan^2(pi/4)=-1/2'

The value of cos^2⁡〖π/16+cos^2⁡〖3π/16+cos^2⁡〖5π/16+cos^2⁡〖7π/16〗 〗 〗 〗...👇

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`2sin^(2)pi/6 +\"cosec\"(7pi)/(6)cos^(2)pi/3=3/2`

`int_0^(pi/6)cos^4 3thetasin^2 6theta dtheta`

Evaluate for theta between 0 and 2pi

`cot^(2)pi/6+\"cosec\"(5pi)/(6) + 3tan^(2)pi/6=6`

'2sin^(2pi/6)+cosec^2(7pi/6)cos^2(pi/3)' || `2sin^(2)pi/6 +\"cosec\"(7pi)/(6)cos^(2)pi/3=3/2`

Find the solutions to a trig equation between 0 and 2pi

Find `theta` for which the expression `sin(theta+pi/6)+cos(theta+pi/6)` attains maximum value

The value of 2 sin⁡(π/8) sin⁡〖(2π/8) sin⁡〖(3π/8) sin⁡〖(5π/8) sin⁡〖(6π/8) sin⁡(7π/8) 〗 〗 〗 〗...👇

Four quadrant and sign convention by Alakh Pandey Sir🔥🔥🔥Basic mathematics#physicswallah #alakhsir

"The value of `cos^2(pi/6+theta)-sin^2(pi/6-theta)` is ...... A) `1/2 | Class 11 Maths | Doubtnut

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