微積分ヘルプ: 積分 ∫ 1/((x^2-1)^(3/2) ) dx - 三角関数の置換による積分

Integral of x^2/(x^2+1)

Evaluate the Integral (x^2 + 1)(x^3 + 3x)^4 dx using the substitution rule

微積分 || 積分 || (x⁴+3x²-1) と (x+2/x²) の極限での積分。

Integration By Partial Fractions

Integral of 1/(1+x^2)^(3/2) (substitution)

Integral of x/(1+x^2)^(3/2) (substitution)

Q139 | ∫(x^3+1)(x-2)/(x^2-x-2) dx | Integral of (x3+1)(x-2) / x2 - x - 2

Integrate (x^1/2) / 1+(x^3/2)^1/2 | Class 12 CBSE 2025 Board exam tough question, can you solve it?!

Integral of x^2/(1+x^3)

Integral of x^3 / ( x^2 + 1)^3 dx

integrate (2x + 1)/((x ^ 2 + 4x + 1) ^ (3/2)) dx — Well Explained

Evaluate the Integral x^2 sqrt(x^3 + 1) dx with u substitution u = x^3 + 1

微積分ヘルプ: 積分 ∫ 1/(x^2-1)^(3/2) dx - 三角関数の置換による積分

Integration (Calculus)

Evaluate the Integral. Partial Fraction Decomposition (x^2 +1)/((x-3)(x-2)^2) dx

`int_0^1 (x^2(1-x^2)^(3/2)dx`

Integration :- limit -1 to 3/2 mod xsinπx

Integral of x^3/sqrt(x^2+1) (substitution)

`int(3x^2+1)/((x^2-1)^3) dx`