結果 : integral 0 to 1 log 1 + x / 1 + x ^ 2 dx
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Evaluate int 0 to 1 log(1+x)/(1+x²)dx | integrate log(1+x)/(1+x^2) from 0 to 1 #cbsepyqs

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`int_0^1 log(1+x)/(1+x^2)dx`を評価する

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integrate log(1+x)/(1+x^2) from 0 to 1

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Show that Integral 0 to 1 log(1+x)/(1+x^2) dx =π/2 log2 | Integration of log(1+x)/(1+x^2) dx

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7#DefiniteIntegration Integral 0 to 1 Log [(1 + x) by 1 + x²] dx

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`int_(0)^(1) log (1/x-1) dx =`

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4,213 回視聴 - 5 年前
6:26

Integrate 0 to 1 log(1+x)/(1+x)^2 dx

Priti Institute
95 回視聴 - 3 年前
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Evaluate the integral from limit 0 to 1 log(1+x)/1+x^2 dx

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show that int 0 to 1 log(1+x)/1+x² dx =π/2 log 2 in telugu by #skydhoni #definiteintegrationskydhoni

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Q46 | Integral 0 to 1 log 1/x - 1 dx | Integrate log 1/x - 1 dx from 0 to 1 | Integrate log(1/x-1)dx

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integrate 0 to a 'ln(1+ax)/(1+x^2)' || Evaluate `int_0^a(log(1+a x)/(1+x^2)dx)`

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3,852 回視聴 - 3 年前
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∫_0^1log (1+x)/(1+x^2) d x=π/8(log 2)

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