Q91 | ∫ⅇ^x (log⁡x+1/x^2 )ⅆx

Integrate 2 to e 1/logx - 1/(logx)^2

`I=int e^x(logx-1/(x^2))dx` を求めよ

Integrate 1/logx - 1/(logx)^2

Q163 | ∫ 1 / x(log⁡x )^2 dx | Integral of 1 / x (log x)2 | Integration of 1 by x logx whole square

Integration [log(logx)+1/(logx)^2]dx

`int{(1)/((logx))-(1)/((logx)^(2))}dx=?`

Q160 | Evaluate ∫(1+log⁡x)^2/x dx | Integral of 1 + log x whole square by x | Integrate(1+log⁡x)^2/x

#NCERT Book Solution | Exercise 7.2 Q18 | #cbseclass12 | #Board_Exam | #Integration by Substitution

【全パターン網羅】数3の積分で無双して、ライバルに差をつけろ！

Q92 | Integrate ∫ {1/log⁡x -1/(log⁡x)^2} dx | Integration of 1 by log x - 1 by log x whole square dx

integrate log(1+x)/(1+x^2) from 0 to 1

Q12 | ∫1/(x(1+log⁡x)^2) | Integral of 1 / x(1+log⁡x)^2 | Integration of 1 by x 1+log⁡x whole square

integration of log (1+x^2) dx | integrated by log 1 plus x square dx | integration by parts

Q13 | Integral of (log(logx) + 1/(logx)²) dx | Integration of (log(logx) + 1/(logx)²)

log x/(1+log x)^2 dx を積分 ||クラス 12 の統合ソリューション |不定積分 - 5

Q102 | Integrate ∫log⁡x/(1+log⁡x)^2 dx | Integration of logx by 1 + logx whole square dx | Class 12

Evaluate integral : ∫ (1 + logx)²/x dx

∫_0^1log (1+x)/(1+x^2) d x=π/8(log 2)

【永久保存版】これを見れば数Ⅲの微分が全て分かります。