積分(logx)^2/(1+x^2)

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The value of `int_(1)^(e^(2)) (dx)/(x(1+logx)^(2))`is

integrate log(1+x)/(1+x^2) from 0 to 1

integration of log (1+x^2) dx | integrated by log 1 plus x square dx | integration by parts

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Integrate 1/x[(log x)^2-3 log x -4] #cbse2024 #integrals

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0 から 1 までの積分 logx/sqrt(1-x^2) dx

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`int[1/logx-1/(logx)^2]dx=`

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`int_(1)^(2)x log x dx =`

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`int{(1)/((logx))-(1)/((logx)^(2))}dx=?`

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How to Integrate logx/(1 + logx)^2 very important CBSE class 12/jee/CPT term 2 class12 sample paper

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