`int(1)/(sqrt(5-.(x^(2))/(4)))dx`

Integral of (x+1)/sqrt(x^2+2x+5) (substitution)

227. Integral de dx entre raíz cuadrada de 5 - x^2, aplicando fórmula

Integral 1/sqrt(x^2+2x+5) Using Trig Substitution

不適切な積分の例 5: 1/sqrt(x-2)

整数 1/(4 + 5x^2)

1/(2x+5) dx の不定積分

Integral of (x^5) sqrt(x^2 + 1)

Integral of 1/(x^2-2x+5) (substitution + substitution)

1/sqrt(5x)の積分

sqrt(1 + x^2) x^5 を積分するための置換法を理解する手順

`int(dx)/(sqrt(x(5x-2)))=`

`int (3x+1)/sqrt(5-2x-x^2) dx`

Integral of 1/(sqrt(5x+3)+sqrt(5x-2)) dx

100 integrals (world record?)

Definite Integration Using Trigonometric Substitution: Int(1/sqrt(x^2-9),x,3,5)

Integrate (5x+1)/(2x²+4x+3) wrt x

Integral of 1/ [ x sqrt( 1 + 2x^5 + 5x^10) ]

Find the following integrals : ∫ dx/root over 5x^2-2x

Integral of 1/sqrt(1-x^2) (substitution)