10. ∫ (x–1)√(5–4x–x²) dx Integrate (x–1) sqrt(5–4x–x²) Antiderivative calculus Math Star Industries🌻
Ejercicio 29| Integración por Sustitución de la integral 1/ raíz cuadrada de (5-X^2) dx
Example of how to integrate with u-Substitution x sqrt(5x^2) - 4 dx
Evaluate the definite integral over [1, 4] for sqrt(5/x) dx. Evaluation Theorem
1/(2x+5) dx の不定積分
sqrt(1 + x^2) x^5 を積分するための置換法を理解する手順
Use substitution to evaluate the Integral dx/sqrt(5x + 3)
Integral of 1/(sqrt(5x+3)+sqrt(5x-2)) dx
Calculus - Integration - Integral of (5x + 3 ) * sqrt( 2x -1 )
integrate 1/sqrt(5x^2-2x) || `int (dx)/sqrt(5x^(2)-2x)`
形式 1/ SQRT(ax^2+bx +c) dx || の積分に基づく問題1/X^2+2X+2 の積分
Calculus Help: Integral from 1 to 5 xdx/ sqrt(5-x) - Integration by Substitution
integrate sqrt(5 - 2x + x ^ 2) dx || KCET 2023 || 12th/PUII Integration
int(1,4) sqrt(5/x)、積分を評価します。
Integral 1/sqrt(x^2+2x+5) Using Trig Substitution
Evaluate:∫x2/(1+5x)dx x∈[-2,2] Intrgration 12th Maths CBSE JEE NDA
不適切な積分の例 5: 1/sqrt(x-2)
integrate '1/4throot((x-1)^3(x+2)^5) dx' || Evaluate: int1/(root(4)((x-1)^3 (x+2)^5)\ dx .
Evaluate the Integral. Partial Fraction Decomposition. (x^2 -5x +16)/((2x+1)(x-2)^2)
#Integrals || Evaluate integral of (2x+5) by \sqrt{x^2-2x+10} dx