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Let I = ∫▒e^x/(e^4x+e^2x+1) dx, J = ∫▒e^(-x)/(e^(-4x)+e^(-2x)+1) dx Then the value of J-I equals:
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The equation e4x + 8e3x+ 13e2x - 8ex +1= 0, x∈ R has
Q) Integration ∫ (e^4x - 1)/(e^4x +1) d𝑥 2026 Integration PYQ 2025 MathsClass 12 #maths #cbse2026
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