Integral of (x^5) sqrt(x^2 + 1)
Integrate(sqrt (5-4x-x^2 ))
限界 2 と限界 3 の間の sqrt(x)/[sqrt(5-x) + sqrt(x)] の定積分を求めます。
Integral of (x+1)/sqrt(x^2+2x+5) (substitution)
Evaluate: \( \int \sqrt{\frac{5-x}{x-2}} d x \)
積分 36: int x^3 sqrt(5-x^2) dx
Integrate x^5 sqrt(2-x^3) dx
3. Integrate ∫ √(5–2x + x²) dx, int sqrt(5–2x+x²)dx : Antiderivative calculus NEB 12 "MSI" easy 💥🌻
`int(1)/(sqrt(5-.(x^(2))/(4)))dx`
100 integrals (world record?)
Integration 7 Marks Important Question 16 | √(5-x)/(x-2)
`int(dx)/(sqrt(x(5x-2)))=`
Evaluateint sqrt(5-2x-x^2) dx | CLASS 12 | METHODS OF INTEGRATION | MATHS | Doubtnut
微積分: ∫ √(5+4x-x^2 ) dx の積分 - sqrt(5+4x-x^2) の積分 - 三角関数の代入
統合 | 5x√(2x+3) dx
Q54、sqrt(x^2+4x+5)の積分、平方完成した三角積分
227. Integral de dx entre raíz cuadrada de 5 - x^2, aplicando fórmula
#Integrals || Evaluate integral of (2x+5) by \sqrt{x^2-2x+10} dx
Find the following integrals : ∫ dx/root over 5x^2-2x
Example of how to integrate with u-Substitution x sqrt(5x^2) - 4 dx