結果 : integral of x^5 sqrt(1+x^2)
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Integral of (x^5) sqrt(x^2 + 1)

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u置換による積分(x - 5)sqrt(x + 2)の積分

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∫6x+5.sqrt 6-2x^2+x dx

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y = sqrt(x-1), x = 2, x = 5, y = 0; about the x-axis

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If sqrt(3x - 5) + sqrt(x -1) = 2, what is the value of x

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`int(x-5)sqrt(x^2-1)dx=`

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Domain and range of square root function #education #exam #linearalgebra #maths #mathstricks #math

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