結果 : integrate log(sinx) - log(2 cos x) dx from 0 to pi/2
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integrate [log(sin x) - log(2cos x)] dx from 0 to pi/2

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Prove that: `int_(0)^(pi//2) log (sin x) dx =int_(0)^(pi//2) log (cos x) dx =(-pi)/(2) log 2`

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