積分 (x^2 + 1)/sqrt(x^3 + 3x) dx

Integral of x^3/sqrt(x^2+1) (substitution)

Integral of (x+1)/sqrt(x^2+2x+5) (substitution)

(Method 1) Integral of x^3/sqrt(1-x^2) (substitution)

Evaluate the Integral x^2 sqrt(x^3 + 1) dx with u substitution u = x^3 + 1

Q62 | Integral 1 to 2 root x / root 3 - x + root x dx | Integrate sqrt(x) / sqrt(3-x)+sqrt(x) dx

Integral of x^3 / ( x^2 + 1)^3 dx

Integral x^3*sqrt(x^2 - 1)

Handling a Weird Infinite Function [MIT Integration Bee 2018]

Evaluate definite integral (x^2 sqrt(x^3 +1)) dx over [0, 2] using method of substitution

100 integrals (world record?)

Integral of sqrt(x)/sqrt(1-x^3) (substitution)

Integral Practice #4: integral of (x^3)(sqrt(x^2 + 1)) (MIT integration bee 2016 qualifying round)

Integral of x^3/sqrt(x^2+4) (substitution)

Integral Practice #7: indefinite integral of ((square root of x)/(1 + cubed root of x))dx

Integral of 1/(x^(1/2) + x^(1/3)) (substitution)

Integral of 1/(1+x^2)^(3/2) (substitution)

Integral of (x^3)*sqrt(1-x^2) (substitution)

(Method 4) Integral of x^3/sqrt(1-x^2) (by parts)

3x^2 * sqrt(x^3 + 1) dx を積分します