置換を用いた不定積分: Int(2x^4*sqrt(5+3x^5),x)

Integration of 4x+6/x^2+3x+100

#Integrals || Evaluate integral of (3x-2) by \sqrt{4x^2-4x-5} dx

integral of 3 / 4x² - 4x + 5 dx

Integrate (1-x)(2+3x)(5-4x)dx |Integration|Calculas|Class 12|Diploma|B.Tech|Maths|Aptitude|11th

Integration using Substitution { dx/(5-3x) }

Integral of [(3x+2)/(x^2+4x+9)]dx #integration

部分分数による積分

Derivative dy/dx | Calculus problem.

Calculus Help: Integral ∫ (5x^4-3) 2^(x^5-3x+π) dx - Integration by substitution

x=0 から 1 までの (2x^4 - 3x^2 + 5) dx の定積分を求めます。

置換による積分問題#5。 ∫ (2x+3)/(x²+3x+4) dx

integral of dx/x2+4x+8 || integral of dx/x²+4x+8 || Integration of dx/x^2 +4x +8 || #term2

Calculus Help: Integral (4x+5)dx / (2x^2 + 5x + 8) - Integration by Substitution

微積分ヘルプ: 積分 ∫ dx/(3x+4)^2 - 積分 - テクニック

Integral [(3x+2)/(x^2+4x+9)]dx #integral

Derivative of (3x+4)/(2x+5) || Quotient Rule of Differentiation

Differentiation and Integration formula

`int(dx)/(2x^2+3x+5)=`

Integral dx / 4x² - 4x - 7 | Methods of Integration @EAG