Integration 1+cos4x/cotx-tanx dx=

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Integration (1+cos4x)/(cotx-tanx) dx

`(1+cos4x)/(cotx-tanx)`

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`int(1+cos4x)/(cotx-tanx)dx`

`int(1+cos4x)/(cotx-tanx)\\ dx`

`int(1+cos 4x)/(cotx-tanx)dx=`

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Evaluate: `int(1+cos4x)/(cotx-tanx)\\ dx`

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( 44 ) Solution of : integration { ( 1 + cos4x ) / ( cotx - tanx ) } * dx = ?

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If : `int(1+cos4x)/(cotx-tanx)dx=A.cos 4x+B`, then

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If ∫(cos4x + 1) /(cotx-tanx) dx = 1/ß cos 4x+ B then find the value of ß jee test series Indefinite