積分 ∫ cos2x/(1-sin2x) - √(​​1-x) dx - sin2x/cos2x dx - 24(1-x)^5 dx - cos⁡(2-x/3)- 5x/(x^2-25)

微積分ヘルプ: 積分 ∫ (sin2x cos2x dx)/(1+3cos4x ) - 置換積分

Q55 | ∫1/(sin^2⁡x cos^2⁡x) dx | Integration of 1/(sin^2⁡x cos^2⁡x) | Integral of 1/(sin^2⁡x cos^2⁡x)

Integration 1/1-cos2x dX =

Q31 | Integration of 1 - sin 2x / X + cos square x | Integrate (1-sin2x)/(x+cos²x) dx

∫√(1+cos2x)dx, ∫√(1-cos2x)dx, ∫√(1+sin2x)dx, ∫√(1-sin2x)dx|Integrations|Integrals|Lec207

Integrate eˣ √(1 + sin2x) / (1 + cos2x) dx

integration of e^2x(1-sin 2x/1-cos 2x)

Integrate the function ∫ e^2x (1+sin2x/1+cos2x) dx

1/(sin^2(x)cos^2(x)) の積分

微積分ヘルプ: e^2x (1-sin2x)/(1-cos2x) dx の積分 - 部分積分

Integral of (1 + sin(2x) + cos(2x)) / (1 + sin(2x) - cos(2x)) using identities

Integration of cot^-1(sin2x/1-cos2x) | integration of cot inverse x | cot x integration

Integral of root(1-sin2x) | #shorts #maths #integral #calculus

lf `int ( sin 2x- cos 2 x) dx=1/(sqrt(2))sin (2x-a) + C`, then a=

Q184 | ∫ √(sin⁡2x) cos⁡2x dx | Integrate square root sin 2x cos 2x | Integration root sin 2x cos 2x

Integrate (2 + sin 2x) / (1 + cos 2x) e^x dx

integrate sin^2 x cos 2x dx

微積分ヘルプ: sinx cosx (sin2x+cos2x )dx の積分 - 三角関数の恒等式による積分

`int (cos2x)/(sqrt(1+sin2x))dx` の値を求めます