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DOUBLE INTEGRAL Evaluate ∫∫ e^(y/x)dydx

MIT Integration Bee 2006 Regular Season, Round 1

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Change the order of integration, integral 0to1 integral x to\sqrt{2-x^2} x by \sqrt{x^2+y^2}dydx

微積分 2: 積分 - 三角関数の代入 (3/28) SQRT(x^2-x^2) の積分1

Integration of e^-x^2 dx limit from 0 to infinity | Application of gamma function

DOUBLE INTEGRAL ∫∫ dydx/(1+x^2+y^2) を評価します