Integrate(sqrt (5-4x-x^2 ))

integral of 3 / 4x² - 4x + 5 dx

微積分：∫√(5+4x-x^2)dxの積分 - sqrt(5+4x-x^2)の積分 - 三角関数の置換

Part 154 Integration of 1/√(5-4x-2x²)dx, 1/√(8+3x-x²)dx #integration #mathematics #class_12

Integration (Calculus)

Calculus Help: Integral ∫ x^2/√(5-4x^2 ) dx - Integration by trigonometric substitution

微積分ヘルプ: 積分 ∫ dx/(5-4x-x^2 )^2 - 三角関数の置換による積分

Evaluate the integral of x^2 sqrt(4x+5) dx from 0 to 1

Integrate x/(9-4x^2) | Exercise 7.2 Q15 | #cbseclass12 | #Board_Exam | #Integration #ncert

Calculus Help: Integral ∫ (x+2)/(x^2-4x-5) dx - Integration by partial fractions - Techniques

Calculus Help: Integral ∫ (5-4x)/√(12x-4x^2-8) dx - Integration by trigonometric substitution

integration of 1/√5-4x-2x² #cbse #maths #jee #ncert #calculus #shorts

微積分ヘルプ: 積分 ∫ (5-4x)/√(12x-4x^2-8) dx - 三角関数の置換による積分

Q54, Integral of sqrt(x^2+4x+5), trig sub with completing the square

Integration By Partial Fractions

置換を用いた不定積分: Int(2x^4*sqrt(5+3x^5),x)

∫dx/5-2x^2+4x

Integral of 1/sqrt(5 - 4x - x^2)

2/(4x^2 - 4x + 5)の積分

Evaluate the Integral (x+4)/(x^2 +2x +5) dx.