The Integral (Sec^2x)/((Secx + Tanx)^9/2)dx | IITJEE Advanced Solution Indefinite Integration #AYMQB

The integral `int (sec^2x)/(secx+tanx)^(9/2)dx` equals to (for some arbitrary constant `K`) (A) `-

`int(sec^2x)/((secx+tanx)^(9/2))dx`

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