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example 9 show that limit x tend to 0 (e^x+log(1-x/e))/(tanx-x) = -1/2 use l hospital rule

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#NDA_1_2017,#L_Hospital_Rule || What is lim x-tending-0 e^x-(1+x)/x² ||#Class11th ||#limit #Calculas

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Evaluate: lim(x→0) (xe^x –log(1-x))/x^2 using l hospital rule

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limit as x approaches 0 of tanx/x

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Using L hospital rule lim x tends to zero x.e^x-log(1+x)/x^2

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limits | Indeterminate forms (0/0) | lim x → 0 ((1+x)^(1/x)-e)/x

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Find the limit as x approaches 0 for (e^x -e^(-x) - 2x)/(x - sin x). l’Hopital’s Rule

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x→0の場合、lim(x→0)tanx/x=1の証明。

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Evaluate `lim_(x to pi)((1+cosx)/(tan^(2)x)).`

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How to prove lim x→0 (eˣ - 1)/x = 1 ? | Limit | Math |

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underset(x to 0^(+))lim log_(tan x) (tan 2x) is equal to | CLASS 12 | LIMITS AND DERIVATIVES | ...

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