If log2, log(2^x. -1) and log(2^x+3) are three consecutive terms of an AP, then the value of x is

マイナス乗とは？2分の1乗とは？基本から丁寧に解説

異なる底を持つ対数方程式を解きます | log_2(x) + log_5(x)= 4。

Resolver log2(x−1) + log2(x+ 2) = 2

Solving logarithmic equation: log3(x-1)-log3(x+2)=2

(log)_4(x-1)=(log)_2(x-3)\nの解の数は (a)\n 3 (b)\n1 (c) 2\n(d) 0 | 12 | LOGA...

Quadratic Equation; he sum of the roots of the equation x + 1 – 2log2 (3 + 2x) + 2log4(10 – 2-x) = 0

Simplify expression 2 log 3/2 - log 5/3 + 3 log 2 + 1/2 log 25. Logarithms

Show that log(1+e^x) = log 2 + x/2 + x^2/8 - x^4/192 + ........ by Maclaurin's Theorem/Series |Maths

対数方程式を解く

【全パターン網羅】数3の積分で無双して、ライバルに差をつけろ！

How to Solve Logarithm Questions in 10 Seconds...

Let A= {x∈(0,π)-{π/2} ∶ 〖log〗_(2/π) |sinx|+〖log〗_(2/π) |cosx|=2} and B = {x≥0∶ √x (√x- 4)- 3|√x-2|+

対数の商の法則を適用して方程式、log2 (x+4) - log2 (x-3)=3 を解きます。

If `log 2, log (2^n-1) and log (2^n + 3)` are in AP, then n =

#iitjee_mains2024 ,if the domain of function f(x)=log(2x+3/4x^2+x-3)+cos^-1(2x-1/x+2)is(alpha,beta ]

対数 - 簡単な方法!

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LOGARITMA ITU GAMPANG!! Bahas Logaritma Kelas 10 | Study With Jerome Polin

Let S={a:log (9^2a-4 +13)-log (5/2.3^2a-4 +1)=2}. Then the maximum value of B for which the equation