結果 : prove that sec 2 theta cos 2 theta sin 2 theta sec 2 theta 1
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Prove that : cosec^2(θ) + sec^2(θ) = cosec^2(θ)sec^2(θ)... || Class 10 ||

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{1/(sec^2⁡𝜃−cos^2⁡𝜃)+1/(𝑐𝑜sec^2⁡𝜃−sin^2⁡𝜃)}sin^2⁡𝜃⋅cos^2⁡𝜃=(1 −sin^2⁡𝜃⋅cos^2⁡𝜃)/(2+sin^2⁡𝜃⋅cos^2⁡𝜃)

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Prove that, `sec^2theta+cosec^2theta=sec^2theta*"cosec"^2theta.`

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sec^2theta - sin^2theta-2sin^4theta/2cos^4theta-cos^2theta = 1 | RS 10 Ex - 13A Q - 14

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