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If tan θ = 1/√7, then (cosec^2 θ - sec^2 θ)/(cosec^2 θ + sec^2 θ​) is equal to 4/3

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(Sec^2 theta - 1) (Cosec^2 theta -1) is equal to

Prove that (sec^3 θ)/(sec^2 θ-1)+(cosec^3 θ)/(cosec^2 θ-1)=secθ⁡cosecθ(secθ+cosecθ) CBSE 2016

Q9 | Prove that sec square theta - 1 into cosec square theta - 1 | (sec^2⁡θ-1)(cosec^2⁡θ-1) = 1

`((1)/(sec ^(2)-cos ^(2)theta)+(1)/(cosec ^(2)theta -sin ^(2)theta ))sin ^(2) theta cos ^(2

Prove that : cosec^2/cosecθ-1 - cosec^1 θ/cosecθ+1 = 2 sec^2 θ.

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Prove that coseca/coseca-1 + coseca/coseca+1=2 sec^2a | prove that (cosec theta)/(cosec theta-1)

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Given `tantheta=1/sqrt5` what is the value of `(cosec^2theta-sec^2theta)/(cosec^2theta+sec^2th

Prove sec^3theta/sec^2theta-1+cosec^3theta/cosec^2theta-1=sectheta * cosectheta(sectheta+cosectheta)

Class 10 Maths (Trigonometry) Example-15, Ncert, Using the identity sec^2 theta = 1+ tan^2 theta

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Prove that : 1/1+sin^2 θ + 1/1+cos^2 θ + 1/1+sec^2 θ + 1/1+cosec^2 θ = 2.