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Integral of sqrt(4-x^2) - Trigonometric Substitution.
sqrt(4-x^2)/x^2 の三角部分積分には、最後に三角部分と参照三角形が必要です。
Solve : `sqrt(2x-6)+sqrt(x+4)=5.`
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dx/sqrt(4 + 2x - x^2) の積分を求めます。
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