The function `f(x)=2x^3-3x^2-12x+4` has
The function `f(x)=2x^(3)-3x^(2)-12x-4` has
Find the absolute maximum and minimum value of f on [-2,3]. F(x) = 2x^3 - 3x^2- 12x +1
The function f(x)=2x^3-3x^2-12x+5 has a minimum at x= | 12 | APPLICATIONS OF DERIVATIVES | MATHS...
The function f(x)=2x^3-3x^2-12x+4 has points of local maximum minimum|BITSAT|VIT|JEE|PYQ|CET|AOD|JEE
Find intervals where f(x) = 3x^4 - 4x^3 - 12x^2 +5 are increasing, decreasing. Local Max, Min
Find points on the curve y= 2x^3 + 3x^2 -12x + 1 where the tangent is horizontal
The function f(x)=2x3-3x2-12x+4 has | Maxima & minima | class 12 mcq | CBSE | JEE-MAIN-2022 | NDA-22
Cambridge AS And A Level Maths | Cambridge AS & A Level Maths 9709/11/M/J/24 | 9709 Maths
For f=X^3 -12x +2 find intervals of increase decrease, max min and test concavity. Sketch graph
Find the critical numbers of the function f(x) = 2x^3 - 3x^2 - 36x
Determine the absolute extrema of the function f(x) = 3x^2 -12x + 5 on the interval [0,3]
変曲点グレード 12
Find stationary points and sketch the curve of y = x^3 - 3x^2. Calculus
Find local Minimum and Maximum || y=2x^3-3x^2-36x+10 || part 2 ||
3x^3-2x^2-12x+8=0の解き方
閉じた区間での絶対極値の検索 f(x) = x^3 - 12x の例
f(x) の最大値と最小値
CBSE XII MATHEMATICS FIND THE MAXIMUM AND MINIMUM VALUE OF THE FUNCTION F(x)=3x^4+4x^3-12x^2+12
Find intervals of concavity, inflection points, local max, min for f(x) = 2x^3 + 3x^2 -36x