結果 : value of cos square pi by 6
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The value of cos^2 (π/6 + x) - sin^2 (π/6 -x) is

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Compute cos(pi/6)

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The value of `cos^2(pi/6+theta)-sin ^2\ (pi/6-theta)` is `adot1/2cos\ 2theta` b. `0` c. `-1/2c

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The value of `cos[cos^(-1) (-sqrt3/2)+pi/6)]`

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The value of `cos^2(pi/6+theta)-sin^2(pi/6-theta)` is

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206 回視聴 - 1 日前
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The value of cos^2⁡〖π/16+cos^2⁡〖3π/16+cos^2⁡〖5π/16+cos^2⁡〖7π/16〗 〗 〗 〗...👇

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"The value of `cos^2(pi/6+theta)-sin^2(pi/6-theta)` is ...... A) `1/2 | Class 11 Maths | Doubtnut

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At what point does sin (x + PI/6) + cos (x + PI/6) attain maximum value in the interval (0,PI/2)?

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Evaluate that : `cos[cos^(-1) (sqrt(3)/2) + pi/6]`

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