The value of cos^2 (π/6 + x) - sin^2 (π/6 -x) is
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The value of `cos^2(pi/6+theta)-sin ^2\ (pi/6-theta)` is `adot1/2cos\ 2theta` b. `0` c. `-1/2c
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Find the value of cos (2*PI/7) + cos (4*PI/7) + cos (6*PI/7).
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The value of `cos^2(pi/6+theta)-sin^2(pi/6-theta)` is
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The value of cos^2〖π/16+cos^2〖3π/16+cos^2〖5π/16+cos^2〖7π/16〗 〗 〗 〗...👇
Find the value of cos inverse cos 7 pi by 6 | Find the value of cos^(-1)(cos 7π/6)
Find the value of the : `cos^2 (pi/6) + cosec (5pi/6) + 3 tan^2 (pi/6)`
"The value of `cos^2(pi/6+theta)-sin^2(pi/6-theta)` is ...... A) `1/2 | Class 11 Maths | Doubtnut
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Evaluate that : `cos[cos^(-1) (sqrt(3)/2) + pi/6]`
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