Find the value of sin^(-1) (- 1/2), arcsin (- 1/2). Inverse Trig Function

Find the value of sin[cos^(-1) (2/3)], sin[arccos(2/3)]. Inverse Trig Function

sin^-1(1/2) 1/2 の逆 sin を求めます。

sin(cos^-1(1/2) + sin^-1(3/5)) の正確な値 三角関数逆複角

Tan(sin^-1(-1/2)) 正確な値を求める

Find the principal value of sin inverse (-1/2)

Find the principal value of sin^(-1)(1/sqrt(2))

Find the principal value of sin⁻¹(-1/2)|CBSE|NCERT|Inverse Trigonometric Functions|12|2022-23|VSAQ

正弦関数の逆関数を求める

QUICKS: OP TRICK FOR sin inverse sin x || SOLVE IN JUST 5 SECONDS!

sin 30° = 1/2 (Why & How?) || Trigonometry

Find the principle value of sin^(-1)(-1/2). Inverse trigonometry Exercise 2.1, question-1.

Why sin(30)=1/2 ?

sin^-1(-sqrt(2)/2) の正確な値を求めます。

Evaluate the following : `sin { 1/2 cot^(-1) . ((-3)/4)}`

Ex2.2 16. find the value of sin-1(sin2π/3) inverse trigonometric functions class 12 ex2.2 question16

Find the principal values of `sin^(-1)(1/2)` (b) `sin^(-1)(-1/(sqrt(2)))`

Find the principal value of: `sin^(-1)(-1/2)`...

Find the value of cos [sin^(-1) (- 4/5)], cos(arcsin( - 4/5)). Inverse Trig Function

Find the principal value of `sin^(-1)` `(1/(sqrt(2)))`...