`sin^(-1)(2x)`

逆三角関数の導関数 sin-1(2x)、cos-1 (x^2)、tan-1 (x/2) sec-1 (1+x^2)

sin^-1(2x+1) の導関数、微積分 1 チュートリアル

show that (i) sin-1(2x√(1-x^2))=2sin-1 x and (ii) sin-1(2x√(1-x^2))=2cos-1 x

Find the value of sin[cos^(-1) (2/3)], sin[arccos(2/3)]. Inverse Trig Function

Q61 | Differentiate sin^(-1)⁡2x | Derivative of sin^(-1)⁡2x | Differentiation of sin inverse 2x

The domain of sin^(-1)2x is | CLASS 12 | INVERSE TRIGONOMETRIC FUNCTIONS | MATHS | Doubtnut

Find the value of `tan { 1/2 sin^(-1) ((2x)/(1+x^(2))) + 1/2 cos^(-1) ((1-y^(2))/(1+ y^(2)))}`

Prove that `2sin^(- 1)x=sin^(- 1)[2xsqrt(1-x^2)]`

Ex2.2 13. tan1/2 sin^(- 1)(2x)/(1+x^2)+cos^(- 1)(1-y^2)/(1+y^2) 12th math exercise 2.2 question13

tan 1 by 2 (sin inverse 2x by 1+x square + cos inverse 1-y^2 by 1+y^2)

tan 1 by 2 ( sin inverse 2x by 1+x square + cos inverse 1-y² by 1+y² )

'sin^-1(2xsqrt(1-x^2))=2sin^-1(x)' || show that 'sin^-1(2x√1-x^2)=2 cos^-1x'

`tan[1/2(sin^(- 1)((2x)/(1+x^2))+cos^(- 1)((1-y^2)/(1+y^2))]`

tan1/2 sin^(- 1)(2x)/(1+x^2)+cos^(- 1)(1-y^2)/(1+y^2) || (sin^ -1(2x/(1+x^2)) ||

If `y = sin^(-1) ((2x)/(1 + x^(2))), "then" (dy)/(dx) ` is equal to

Prove that 2tan-1x = sin-1(2x/(1 + x2)) = cos-1((1 - x2)/(1 + x2)) ||ch2 12th properties 6

Find the domain of `sin^(-1)(2x^(2)+1)`

`sin^(-1)x+sin ^(-1)""2x=(pi)/(3)`

ITF - More Properties / Questions #1 : Prove that 2 sin^-1 x = sin^-1 ( 2x root(1-x^2)