|CLASS11| |Exercise3.3| QueNo-1| |sin^2pi/6+cos^2pi/3-tan^2pi/4=-1/2|
Prove that: sin ^2π/6+cos ^2π/3-tan ^2π/4=-1/2 LHS = sin ^2π/6+cos ^2π/3-tan ^2π/4 = (1/2)^2+(1...
Compute sin(pi/6)
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The maximum value of sin(x+π/6)+cos(x+π/6) for x ∈[0, π/2] is attained at x= (a) π/12 (b) π/6 (c)...
