Proof: tan^2 + 1 = sec^2

Prove the trig identity: 1+tan^2 = sec^2

Prove (tan@+sec@-1)÷(tan@-sec@+1)= (1+sin@)÷ cos@

Prove That (1+Sec A)/(sec A)=(sin^2 A)/(1-cos A)

Prove the trigonometry identity: 1+tan^2x=sec^2x

Verify the Trig Identity sec(x) - tan(x)sin(x) = 1/sec(x)

tan theta/1-cot theta + cot theta/1-tan theta= 1+ sec theta cosec theta

sintheta-costheta+1/sintheta+costheta-1=1/sec theta-tan theta

12th Maths | CH 7 Exercise 7.4 | Day 6 Half Yearly Revision | Sowndarya Ma'am

(tan ∅)/(1-cot ∅)+(cot ∅)/(1-tan ∅)=1+Sec ∅ cosec ∅

`(tan theta)/(sec theta -1)+ (tan theta)/(sec theta +1) = 2 cosec\ theta`

Show that: `1/(sec A-tan A) - 1/(cos A) = 1/(cos A) - 1/(sec A + tan A)`

Prove 1+sec⁡ A/sec ⁡A = sin^2 A/(1-cos A) | Exercise 8.4 Q5 part (iv)

Prove that √((1+Sin A)/(1-Sin A)) = Sec A + Tan A

If sec `theta+tantheta+1=0`,then sec `theta-tan theta` is:

Q30 | Prove that 1 + tan square theta by 1 + sec square theta = secθ | 1+tan^2⁡θ/(1+sec⁡θ)=sec⁡θ

(sec A + tan A) (1 – sin A) equals:

Q96 | Prove that tan⁡A/(1+sec⁡A)-tan⁡A/(1-sec⁡A)=2 cosec⁡A

Q1 | Prove that (1-sin^2⁡θ) sec^2⁡θ=1 | Trigonometric Identities | Gravity Coaching Institute

Grade10 prove that 1/ sec theta - tan theta = sec theta + tan theta