cot^-1(-1) find the inverse of the cotangent of -1

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Prove the trig identity: 1+cot^2 = csc^2

cot^-1(-sqrt(3)/3)

cot/(1 - tan) + tan/(1 - cot) = 1 + tan + cot

Prove that the derivative of cot^(-1) x= -1/(1+ x^2). Derivative of Inverse Trig Functions

If y = cosec^-1 x, then dy/dx = -1/ x(x^2-1)^1/2 or dy/dx = -1/ x(x^2-1)^1/2

cot^-1(sqrt(3))

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Proof of cot^-1(-x) = pi - cot^-1(x)

cot^-1(-x) = pi - cot^-1(x) | arccot(-x) = pi - arccot x

The expression tan⁡A/(1-cot⁡A )+cot⁡A/(1-tan⁡A ) can be written as

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If \( \cot A+\frac{1}{\cot A}=2 \), find the value of \( \cot ^{2} A+\frac{1}{\cot ^{2} A} \)

cot(cos^-1(-sqrt(3)/3))

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Differentiation of cot inverse x | differentiation of cot^-1(x) | differentiation formula proof

tan theta/1-cot theta + cot theta/1-tan theta= 1+ sec theta cosec theta