Angle between two lines:(x+3)/3=(y-1)/5=(z+3)/4,(x+1)/1=(y-4)/1=(z-5)/2(@ComfortUrMaths)
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x+3/3=4-y/5=z+8/6に平行に(-2,4,-5)を通る直線のデカルト方程式を求めます。
3+6 divided by 2 = 6??
Show that the lines x+1/3=y+3/5=z+5/7 and x-2/1=y-4/3=z-6/5 intersect. Also find their point of
例: 指定された直線に平行な直線のパラメトリック方程式
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Show that the lines x-1/2=y-2/3=z-3/4 and x-4/5=y-1/2=z intersect | Three Dimensional Geometry
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Find the foot of the perpendicular from the point (0,2,3)\non the line (x+3)/5=(y-1)/2=(z+4)/3do...
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Find the image of the point `(0,2,3)` in the line `(x+3)/(5)= (y-1)/(2) = (z+4)/(3)`.