4 次多項方程式 x^4 - 2x^3 - 5x^2 + 8x + 4 = 0 の解き方

(x+3)(x+5) Expand and Simplify

Theory of equation : x^4+2x^3-5x^2+6x+2=0,one of the root is 1+i

2 乗因数分解を使用した多項式の 4 乗因数分解

1 分以内に 3 次方程式を因数分解して解きましょう! - 超簡単な裏技

Solve quadratic equation by factorisation

3 次多項式の因数分解 x^3 - 5x^2 + 2x + 8

How To Find the Zeros of The Function

Solve the equation `x^4 + 4x^3 + 5x^2 + 2x-2=0`, one root being `-1+sqrt(-1) `

因数分解を使用して方程式を解く、4x^2 - 5x + 1 = 0

Solve by completing the square | Step by Step Technique

Part 10 || Solve x⁴-4x²+8x + 35 = 0, given that 2+ i√3 is a root

Solve x^4+〖2x〗^3-7x^2-8x+12=0

Ecuaciones de primer grado - Ejercicio 3 | Fantastico Sencillo | Matematicas Quidimat

Solving a quadratic by completing the square

Solving an equation for y and x

1 2 3 4 5 6 7 8 9 10

How to Divide Polynomials using Long Division - Polynomials

FERRARI METHOD #2 - MATHEMATICS- HINDI

Jaldi Wahan Se Hato! IIT Delhi version! #iit #iitjee #iitdelhi