因数分解(x^3+y^3+z^3-3xyz)

`x+y+z=0` の場合、`x^(3)+y^(3)+z^(3)=3xyz` であることを示してください。

If x+y+z=0 Then Show That x3+y3+z3=3xyz | If x+y+z=0 Prove That x3+y3+z3=3xyz

If x+y+z =0, then show that x³+y³+z³ =3xyz

Prove that x³+y³+z³-3xyz=(x+y+z) (x²+y²+z²-xy-yz-zx) Algebraic identity derivation | Bharat Kumar

x+y+z=0 の場合、x3+y3+z3=3xyz | を示します。 Ex 2.5 クラス 9

If x+y+z=0 show that x3+y3+z3=3xyz | Class 9 Maths Ch 2 Ex 2.5 Q13

FACTORISATION OF x³+y³+z³-3xyz = (x+y+z) (x²+y²+z²-xy-yz-zx) | In Hindi

Algebric Formula ||Prove That👉x3+y3+z3-3xyz=(x+y+z)(x2+y2+z2-xy-yz-zx|| Cbse class10th|| NCERT Book.

If x+y+z=0 then show that x3+y3+z3=3xyz

If x+y+z=0, show that x^3+y^3+z^3=3 x y z.

x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)/a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

Factorise : -  x3 + y3 + z3 - 3xyz

if x+y+z=0 prove that x3+y3+z3=3xyz | x+y+z=0show that x3+y3+z3=3xyz

If x+y+z = 0 , show that x3+y3+z3= 3xyz

9th.. x³+y³+z³-3xyz=1/2(x+y+z)[(x-y)²+(y-z)²+(z-x)²]

proof of x^3 + y^3 + z^3 - 3xyz = (x + y + z)(x^2 + y^2 + z^2 - xy - yz - zx)

Partial Differentiation || 𝒍𝒐𝒈(𝒙^𝟑+𝒚^𝟑+𝒛^𝟑−𝟑𝒙𝒚𝒛) || VTU maths || Dr Prashant Patil

if x+y+z=0 prove that x3+y3+z3=3xyz | if x+y+z=0 then show that x3+y3+z3=3xyz

If x+y+z=0,Then Prove that x³+y³+z³=3xyz | Algebraic identity derivation | Bharat Kumar